for y = ax^2 + bx + c
the x of the vertex is -b/(2a)
so for yours, the x of the
vertex = 16/8 = 2
I see (2, -7) as the only point where x = 2
I would now sub x = 2 into the equation to make sure I get -7
The equation f(x) = 4x2 − 16x + 9 represents a parabola. What is the vertex of the parabola?
(2, −7)
( −2, 57)
(4, 9)
( −4, −137)
1 answer