Asked by philip!!!
if 2x^2-(b-4)x-4(b+2)=0
has equal root then.the value of b?
has equal root then.the value of b?
Answers
Answered by
Damon
if two roots are identical
then
(b-4)^2 - 4(2)(-4)(b+2) = 0
b^2 - 8 b + 16 = -32b - 64
b^2 + 24 b + 80 = 0
(b+4)(b+20) = 0
then
(b-4)^2 - 4(2)(-4)(b+2) = 0
b^2 - 8 b + 16 = -32b - 64
b^2 + 24 b + 80 = 0
(b+4)(b+20) = 0
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