Question

Please help !
1.)a catapult launches a boulder with an upward velocity of 122 feet per second. the height of the boulder, h, in feet after t seconds is givin by the function h(t)=-16t^2+122t+10. what is the boulders maximum height ? and how long does it take the boulder to reach its maximum height ? round to the nearest hundredth if necessary.
a.)reaches a maximum height of 15.42 feet after 7.71 seconds
b.)reaches a maximum height of 7.71 feet after 3.81 seconds
c.)reaches a maximum height of 242.56 feet after 7.62 seconds
d.) reaches a maximum height of 242.56 feet after 3.81 seconds.

2.)a ball is thrown with a upward velocity of 28 ft/s. its height h, in feet after t seconds is given by the function h=-16t^2+28t+7. what is the balls maximum height how long does it take the ball to reach maximum height ? round to the nearest hundredth if needed.
a.)reaches a maximum height of 7 feet after 1.75 seconds
b.) reaches a maximum height of 43.75 feet after 0.88 seconds
c.)reaches a maximum height of 17.5 feet after 0.88 seconds
d.)reaches a maximum height of 19.25 feet after 0.88 seconds

Answer 1

Remember your Algebra I. The max height is represented by the vertex of the parabola. As with all quadratics, the vertex is at t = -b/2a. So, for

#1: t = -122/-32 = 3.8125 seconds

use the same logic on #2.

Answer 2

Number 2 is D. yw :)

Answer 3

the answer for #1 is "reaches a maximum height of 242.56 feet after 3.81 seconds." 2022

Answer 4

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