original a momentum = 80*2.5
original b momentum = -68*1.2
total momentum before and after
= 80*.5 - 68*1.2
after
= 80*1 + 68 Vb
which is
final momentum a = 80
final momentum b = total - 80
F on a = (final momentum a - initial momentum a) /0.1
Two basketball players collide head on. play a weighs 80 kg and is travelling 2.5m/s to the right while player b weighs 68 kg and is travelling 1.2 m/s to the left. after collision player a is travelling at 1.0 m/s to the right.
a. what is the change in momentum of player a?
b. if the collision lasted 0.1s what is the average force play b must have exerted on player a during the collision?
c. what is the average force that player a must have exerted on player b during the collision?
d. what is the change in momentum of player b?
e. what is the final velocity of player b?
1 answer
1 answer