Asked by PRELUDE
Prove the identity:
4x=1-8sin^2x+8sin^4x
4x=1-8sin^2x+8sin^4x
Answers
Answered by
Anonymous
Your "identity" makes no sense
I will work on the RS to see where that goes
RS = 1 - 8sin^2 x(1 - sin^2 x)
= sin^2 x + cos^2 x - 8sin^2 xcos^2 x
= going nowhere, unless I have something to aim for
I will work on the RS to see where that goes
RS = 1 - 8sin^2 x(1 - sin^2 x)
= sin^2 x + cos^2 x - 8sin^2 xcos^2 x
= going nowhere, unless I have something to aim for
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