original dimensions s x s
new dimensions; 3s x (s+7)
perimeter new=96=6s+2s+14
8s=82
s=82/8
If the lengths of a pair of opposite sides of a square were tripled and the other pair were each increased by 7 cm,the new figure would be rectangle with a perimeter 96 cm find the dimensions of the original square
2 answers
The square on the hypotenuse