Asked by Petey
How much water would be formed if 3.00 mol NH3 reacted with excess oxygen gas in the following equation?
Given the reaction 4NH3+ 5O2 --> 4NO + 6H2O
A) 2.00 mol
B) 3.00 mol
C) 4.50 mol
D) 6.00 mol
E) None of these
Given the reaction 4NH3+ 5O2 --> 4NO + 6H2O
A) 2.00 mol
B) 3.00 mol
C) 4.50 mol
D) 6.00 mol
E) None of these
Answers
Answered by
bobpursley
3/4=6/x
E.
E.
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