Question

For the graph of a certain quadratic y = ax^2 + bx + c, the vertex of the parabola is (3,7) and one of the x-intercepts is (-2,0). What is the x-coordinate of the other x-intercept?


Thank you for helping me :D

Answer 1

zeros
x = [-b +/- sqrt(b2-4ac)] /2a

vertex therefore at x = -b/a
3 = -b/2a

x intercepts are the same distance each side of 3
one is five to the left of 3
the other must be 5 to the right
3+5 = 8

Answer 2

Thank you! :)