Asked by John

A bottle rocket launches into the air. The equation h=-16t^2+64t+9 gives the height of the ball, h in feet, as a function of t, number of seconds after launch. What is the maximum height the ball reaches? How many seconds does it take the ball to reach that height?

Answers

Answered by Reiny
you are basically looking for the vertex of this downwards opening parabola

the t of the vertex is -b/2a
= -64/-32 = 2 seconds

it will take 2 seconds to reach the maximum height
when t = 2
h = -16(4) + 64(2) + 9
= 73 ft
Answered by Ana
THANK YOU SO MUCH
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