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1 m pendlum on Earth has a period of 2 s. What would it's period be on the moon where the acceleration due to gravity is 1.63 m/s2 ?
9 years ago

Answers

Henry
T = 2pi*Sqrt(L/g) = 6.28*Sqrt(1/1.63) = 4.92 s.

9 years ago

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