I posted the wrong problem for my work provided, although I am struggling to answer both. The correct problem for my work provided is as follows. A car Traveled 132mi at a certain speed. If the speed had been 11mph faster, the trip could have been made in 2hr less time. Find the speed.
This is what I have so far for the paint problem. A+B=5 , A=Bx2
again I know know what steps need to be taken to solve.
Person A can paint the neighbor's house 2 times as fast as Person B. The year A and B worked together, it took them 5 days. How long would it take each to paint the house? So, i know how to setup the problem, but i'm not sure what steps I need to take to solve. This is what I have currently. 1/a+1/b=1/t (t represents time) 132=rt/132=(r+11)(t-2) so t-132/r how do I solve for t? Any help or direction to help would be extremely appreciated, thank you.
4 answers
If it takes A x days, it takes B 2x days.
1/x + 1/(2x) = 1/5
3/(2x) = 1/5
x = 15/2
So, it takes B 15/2 days, and A 15/4 days
1/x + 1/(2x) = 1/5
3/(2x) = 1/5
x = 15/2
So, it takes B 15/2 days, and A 15/4 days
since time = distance/speed,
132/(x+11) = 132/x - 2
x = 22
6 hrs at 22 mph
4 hrs at 33 mph
132/(x+11) = 132/x - 2
x = 22
6 hrs at 22 mph
4 hrs at 33 mph
Thank you Steve.
1 answer