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A car’s headlight contains a parabolic reflector. A special bulb with two filaments is used to produce the high and low beams....Asked by Sandy East Ward
A car’s headlight contains a parabolic reflector. A special bulb with two filaments is used to produce
the high and low beams. The filament placed at the focus produces the high beam and the filament
placed off-focus produces the low beam. The equation of the reflector is x=1/8y^2. How far from the
vertex should the filament for the high beam be placed?
the high and low beams. The filament placed at the focus produces the high beam and the filament
placed off-focus produces the low beam. The equation of the reflector is x=1/8y^2. How far from the
vertex should the filament for the high beam be placed?
Answers
Answered by
Sandy East Ward
I need to know what equation to use!
Answered by
bobpursley
the formula for the reflector is x=1/8 y^2
the location of the focus is 2,0
the location of the focus is 2,0
Answered by
Steve
for the parabola
y^2 = 4px
the vertex is at a distance p from the focus.
y^2 = 4px
the vertex is at a distance p from the focus.
Answered by
Sandy East Ward
How do I find the solution? Is 2 the solution?
Answered by
Sandy East Ward
I got this far: y^2 = 8x
Answered by
Steve
so, 8=4p
p=2
that is the distance from the vertex to the focus. All you need to do is
(a) read what we gave you
(b) think about it a bit
p=2
that is the distance from the vertex to the focus. All you need to do is
(a) read what we gave you
(b) think about it a bit
Answered by
Sandy East Ward
Is this it?
y^2 = 8x
8x = y^2 = 4px
8x = 4px
8 = 4p
8/4 = 4p/4
2 = p
y^2 = 8x
8x = y^2 = 4px
8x = 4px
8 = 4p
8/4 = 4p/4
2 = p
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