h(t)=vi*t-1/2 *32*t^2 +4
dh/dt=0=vi-32t, so at at h max
t=79/32
and max height is
hmax=79*79/32-1/2 * 32*(79/32)^2+4
Use a(t) = -32 ft/sec2 as the acceleration due to gravity. (Neglect air resistance.)
A ball is thrown vertically upward from a height of 4 feet with an initial velocity of 79 feet per second. How high will the ball go? (Round your answer to two decimal places.)
1 answer