Asked by Sam
Use
a(t) = −9.8
meters per second per second as the acceleration due to gravity. (Neglect air resistance.)
A canyon is 2300 meters deep at its deepest point. A rock is dropped from the rim above this point. Write the height of the rock as a function of time t in seconds. (Use the canyon floor as position 0.)
f(t) = ?
a(t) = −9.8
meters per second per second as the acceleration due to gravity. (Neglect air resistance.)
A canyon is 2300 meters deep at its deepest point. A rock is dropped from the rim above this point. Write the height of the rock as a function of time t in seconds. (Use the canyon floor as position 0.)
f(t) = ?
Answers
Answered by
Damon
a = -9.8
v = Vi - 9.8 t
h = Hi + Vi t +(1/2) a t^2
h = 2300 + 0 t - 4.9 t^2
= 2300 - 4.9 t^2
v = Vi - 9.8 t
h = Hi + Vi t +(1/2) a t^2
h = 2300 + 0 t - 4.9 t^2
= 2300 - 4.9 t^2
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