Asked by Ellen
Solve the volume of a cylinder with diameter (4 +2x)m, height (5x+1)m
v=pi [(4+2x) x (5x+1)]
v=pi [(4+2x) x (5x+1)]
Answers
Answered by
Kent
Volume of a cylinder=pi*radius^2*height
If diameter=4+2x, then radius=2+x
radius^2=x^2+4x+4
Volume=pi(5x^3+10x^2+20x+x^2+4x+4)
Volume=pi(5x^3+11x^2+24x+4)
Depending on what your x value is, plug it in to get an answer
If diameter=4+2x, then radius=2+x
radius^2=x^2+4x+4
Volume=pi(5x^3+10x^2+20x+x^2+4x+4)
Volume=pi(5x^3+11x^2+24x+4)
Depending on what your x value is, plug it in to get an answer
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