Asked by cindy

prove that 2sinA + 1 / cosA+sin2A=secA

9 years ago

Answered by Steve

(2sinA+1)/(cosA+sin2A)
= (2sinA+1)/(cosA+2sinAcosA)
= (2sinA+1)/[cosA(1+2sinA)]
= 1/cosA
= secA

9 years ago

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