Asked by Anonymous
Find the length of a chord intercepted by a central angle of 25 degrees in a circle of radius 30 feet
Answers
Answered by
Reiny
let the length of the chord be 2x ft
Drop a perpendicular from the central vertex to the chord
then sin 12.5 = x/30
x = 30sin12.5
2x = 60sin12.5 = 12.9864
or by cosine law:
let the length of the chord be c
c^2 = 30^2 + 30^2 - 2(30)(30)cos25
= 168.64598..
c = 12.9864 , same as above
Drop a perpendicular from the central vertex to the chord
then sin 12.5 = x/30
x = 30sin12.5
2x = 60sin12.5 = 12.9864
or by cosine law:
let the length of the chord be c
c^2 = 30^2 + 30^2 - 2(30)(30)cos25
= 168.64598..
c = 12.9864 , same as above
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.