Asked by Branndon
Each of my digits is add. They add up to 12. I have 4 digits. What am I?
Answers
Answered by
Reiny
add = odd ??
notice that
12 = 7+5+1+1
or
12= 3+5+3+1
12 = 7+3+1+1
12 = 9+1+1+1
see if you can find any others.
now each of my choices can be arranged in different orders
7,5,1,1 ---> yields 4!/2! or 12 of them
3,5,3,1, yields 4!/2! = 12 of them
7,1,1,1,1
etc
one of them is 5711 another is 3171
notice that
12 = 7+5+1+1
or
12= 3+5+3+1
12 = 7+3+1+1
12 = 9+1+1+1
see if you can find any others.
now each of my choices can be arranged in different orders
7,5,1,1 ---> yields 4!/2! or 12 of them
3,5,3,1, yields 4!/2! = 12 of them
7,1,1,1,1
etc
one of them is 5711 another is 3171
Answered by
Reiny
scrap the 7,5,1,1 combination, they don't add up to 12
also scrap the 7,1,1,1,1, there should only be 4 digits.
also scrap the 7,1,1,1,1, there should only be 4 digits.