Asked by Anonymous
Roy has a patio that covers 434 ft ^2. He wants to increase his patio 196 ft ^2 by adding 4 ft to both the length and width. The length of the original patio is 3 ft more than twice the width. What is the length of the new patio
Answers
Answered by
Anonymous
First, Area=Length*Width
Original Length=3+2*Width
434=Original Length*Original Width
434=(3+2*Width)*Width
434=3*Width+2*Width^2
I solved by graphing, you can do another way if you want.
Width is 14 ft. Original Length is 31 ft.
Add 4 and you get the answer: 35 feet
Original Length=3+2*Width
434=Original Length*Original Width
434=(3+2*Width)*Width
434=3*Width+2*Width^2
I solved by graphing, you can do another way if you want.
Width is 14 ft. Original Length is 31 ft.
Add 4 and you get the answer: 35 feet
Answered by
Anonymous
Ty!
Answered by
Reiny
Algebraic way:
original width = x
original length = 2x+3
x(2x+3) = 434
2x^2 + 3x - 434 = 0
(x - 14)(2x + 31) = 0
x = 14 or x = -31/2 , which I will reject
original width is 14 ft
original length is 31 ft
new width = 18
new length = 35
original width = x
original length = 2x+3
x(2x+3) = 434
2x^2 + 3x - 434 = 0
(x - 14)(2x + 31) = 0
x = 14 or x = -31/2 , which I will reject
original width is 14 ft
original length is 31 ft
new width = 18
new length = 35
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