Asked by SkatingDJ
Find the area of a hexagon with the indicated apothem:
6 sqr root 3
108 sqr root 3 in.^2
432 sqr root 3 in.^2
96 sqr root 3 in.^2
216 sqr root 3 in.^2
Last question, don't know. Please help? Thanks
6 sqr root 3
108 sqr root 3 in.^2
432 sqr root 3 in.^2
96 sqr root 3 in.^2
216 sqr root 3 in.^2
Last question, don't know. Please help? Thanks
Answers
Answered by
Reiny
Area = 1/2 x perimeter x apothem
= 1/2 (6s)(6√3)
once you tell me what the side (s) of the hexagon is, we an finish the question
= 1/2 (6s)(6√3)
once you tell me what the side (s) of the hexagon is, we an finish the question
Answered by
SkatingDJ
They don't tell you the sides, the apothem is all they give you.
Answered by
Reiny
So, I guess we can't find the area, since we need the side
Answered by
SkatingDJ
Hm, I mean, there has to be a way to figure the side out with just the apothem. Problem is that I'm not good with formulas or square roots.
First off, what is the apothem? What is 6 square root 3?
First off, what is the apothem? What is 6 square root 3?
Answered by
Reiny
ok, ok
I stand corrected, there is a way, we have an angle.
The apothem is the distance from the centre to the midpoint of a side
Let's look at one of the triangles of the hexagon.
It has a central angle of 60
so in a right-angled triangle formed by the apothem and half the base, I'll call it x
x/6√3 = tan 30
x = 6√3tan30
base = 12√3tan30= 12
area = Area = 1/2 x perimeter x apothem
= (1/2)(72)(6√3)
= 216√3 units^2
I stand corrected, there is a way, we have an angle.
The apothem is the distance from the centre to the midpoint of a side
Let's look at one of the triangles of the hexagon.
It has a central angle of 60
so in a right-angled triangle formed by the apothem and half the base, I'll call it x
x/6√3 = tan 30
x = 6√3tan30
base = 12√3tan30= 12
area = Area = 1/2 x perimeter x apothem
= (1/2)(72)(6√3)
= 216√3 units^2
Answered by
Raaayleeee
Unit 5: Area
Lesson 4: Perimeters and Areas of Similar Figures
Perimeters and Areas of Similar Figures Quiz
1) A - 14.04cm^2
2) A - 34cm^2
3) A - 144.5cm^2
4) D - 12cm
5) A - 144 + 72squareroot3
6) B - 15.9ft^2
7) D - 72squareroot3
8) B - 73.5squareroot3cm^2
9) C - 5 : 4 and 25 : 16
10) C - 3181m^2
11) A - $81.25
12) D - the area would not change
13) D - 216squareroot3in^2
100%
Lesson 4: Perimeters and Areas of Similar Figures
Perimeters and Areas of Similar Figures Quiz
1) A - 14.04cm^2
2) A - 34cm^2
3) A - 144.5cm^2
4) D - 12cm
5) A - 144 + 72squareroot3
6) B - 15.9ft^2
7) D - 72squareroot3
8) B - 73.5squareroot3cm^2
9) C - 5 : 4 and 25 : 16
10) C - 3181m^2
11) A - $81.25
12) D - the area would not change
13) D - 216squareroot3in^2
100%
Answered by
Timmy!!!
Raaayleeee is right
Answered by
Thanks Raaayleeee
You are 100% correct! Thanks!!
Answered by
the hacker known as 4chan
Raaayleeee's answers are correct but the letters have changed.
Answered by
Trust me
Raaayleeee's letters have changed so just go by the actual answer she gives those are all correct
Answered by
T
Thanks raaayleeee
Answered by
leelee duhh
thankyouuuu
Answered by
I just watched Given
Thank you! they're all correct!
Answered by
Chocolate
Raaayleeee is still right! :)
Answered by
I like anime
I like anime ok but that inappropriate here sorry ye letters have changed but raaayleeee is still correct tysm helped me a lot. PPl try not to use the answer directly try to use them and learn the proccess of how to get to thata point anyway you guys have a great day/night alrighty? cya just saying I am also "Will I be here for Eternity" or something like that I forgor. BYE!
Answered by
Bot
No problem, glad to help! Have a wonderful day ahead!