Asked by Rose
The reaction through which carbon changes from graphite to diamond form is represented by the equation
C(graphite) ---> C(diamond) delta H: ?
Using the reactions below, determine the amount of heat absorbed in the change of one mole of graphite to one mole of diamond
C(graphite) + O2 ---> CO2(g) delta H is -393.5 kJ/mol
C(diamond) + O2(g) ---> CO2(g) Delta H is -395.4 kJ/mol
Do i do the same thing where i add the two equations of delta H???
C(graphite) ---> C(diamond) delta H: ?
Using the reactions below, determine the amount of heat absorbed in the change of one mole of graphite to one mole of diamond
C(graphite) + O2 ---> CO2(g) delta H is -393.5 kJ/mol
C(diamond) + O2(g) ---> CO2(g) Delta H is -395.4 kJ/mol
Do i do the same thing where i add the two equations of delta H???
Answers
Answered by
bobpursley
deltaH=Hgraphite to CO2+HCO2 to graphite
= -393.5kJ/mol+395.4kJ/mol
= -393.5kJ/mol+395.4kJ/mol
Answered by
Rose
So i would change the sign of the second equation and add them?
Answered by
bobpursley
Yes, you have reversed the reaction to get diamond. sign of delta H reverses.
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