Asked by SkatingDJ
A piece of art is in the shape of an equilateral triangle with sides of 21 in. What is the area of the piece of art to the nearest tenth?
311.8 in.^2
381.9 in.^2
155.9 in.^2
191.0 in.^2
Please help?
311.8 in.^2
381.9 in.^2
155.9 in.^2
191.0 in.^2
Please help?
Answers
Answered by
bobpursley
let s be half the perimeter, or 63/2
area=sqrt[s*(s-21)(s-21)(s-21)l
area= sqrt(63/2*(21/2)^3)
= sqrt(21*3/2 ( 21/2)^3
= 21*21/2 sqrt3=190.958602
= 191.0 to the nearest tenth.
area=sqrt[s*(s-21)(s-21)(s-21)l
area= sqrt(63/2*(21/2)^3)
= sqrt(21*3/2 ( 21/2)^3
= 21*21/2 sqrt3=190.958602
= 191.0 to the nearest tenth.
Answered by
SkatingDJ
Thank you, bob!!!:)
Answered by
connexus boy
wot does s stand for
Answered by
Molly
191.0
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