Asked by SkatingDJ

A piece of art is in the shape of an equilateral triangle with sides of 21 in. What is the area of the piece of art to the nearest tenth?

311.8 in.^2
381.9 in.^2
155.9 in.^2
191.0 in.^2

Please help?

Answers

Answered by bobpursley
let s be half the perimeter, or 63/2

area=sqrt[s*(s-21)(s-21)(s-21)l
area= sqrt(63/2*(21/2)^3)
= sqrt(21*3/2 ( 21/2)^3
= 21*21/2 sqrt3=190.958602
= 191.0 to the nearest tenth.
Answered by SkatingDJ
Thank you, bob!!!:)
Answered by connexus boy
wot does s stand for
Answered by Molly
191.0
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