Asked by Erica
I am lost. I have to create a buffer using NH4CL and 0.10 M NH3. I have to chose how much of the reagent to use in order to get a concentraion between 0.01 and .5 M. Then after I come up with the recipe for that I have to calculate the pH baces on the concentrations using the Henderson-Hasselbalch equation. We have not gone over this in class so I'm on my own and lost. Can anyone help??
Answers
Answered by
DrBob222
Usually you know the pH but you don't show that. You know pKa for NH3 to be about 9.26 but use the number in your text/notes. If you want the buffer to be between 0.01 and 0.5, why not choose say 0.3.
If base + acid = 0.3, then
base = 0.1 and acid must be 0.2 so
pH = pKa + log base/acid
pH = 9.26 + log 0.1/0.2 and
pH = approx 8.8 and that's in the ballpark of where it should be. You also don't say how much to make. Let's make a liter of solution.
So you have 0.10 M NH3. Start with that.
You want NH4Cl to be 0.2 M.
So you want to add 0.2 mol NH4Cl to the 1L of 0.1M NH3 and mix.
grams NH4Cl = mols NH4Cl x molar mass NH4Cl or g NH4Cl = 0.2 x molar mass NH4Cl = ?
This should do it assuming there are no limits as to pH you want the buffer or the amount of buffer you are to prepare.
If base + acid = 0.3, then
base = 0.1 and acid must be 0.2 so
pH = pKa + log base/acid
pH = 9.26 + log 0.1/0.2 and
pH = approx 8.8 and that's in the ballpark of where it should be. You also don't say how much to make. Let's make a liter of solution.
So you have 0.10 M NH3. Start with that.
You want NH4Cl to be 0.2 M.
So you want to add 0.2 mol NH4Cl to the 1L of 0.1M NH3 and mix.
grams NH4Cl = mols NH4Cl x molar mass NH4Cl or g NH4Cl = 0.2 x molar mass NH4Cl = ?
This should do it assuming there are no limits as to pH you want the buffer or the amount of buffer you are to prepare.
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