Asked by oscar

x^2-2xy=3...1
3x^2-y^2=26...2
Answered by Steve
From #1, y = (x^2-3)/(2x)
so, in #2,

3x^2 - ((x^2-3)/(2x))^2 = 26

Or, assuming x≠0,

(11x^4-98x^2-9)/(4x^2) = 0
(x-3)(x+3)(11x^2+1) = 0
x = -3 or 3 or complex values.
Answered by olami
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