In the figure below, a wheel of radius 0.275 m is mounted on a frictionless

Question

horizontal axle. A massless cord is wrapped around the wheel and attached to a
1.95 kg box that slides on a frictionless surface inclined at angle θ = 32.7 ° with the
horizontal. The box accelerates down the surface at 2.15 m/s2. Calculate the
rotational inertia of the wheel about the axle.

Answer 1

mg sinθ = ma + Iα
where α = a/r
solve for I

Although without a diagram I can't be certain

Answer 2

Don't forget that torque=I(alpha), so multiply mg sin(theta) and ma both by r so you'll be in the same units.