Asked by Anonymous

A youth organization collected nickels and dimes for a charity drive. By the end of the​ 1-day drive, the youth had collected ​$57.75. If there were five times as many dimes as​ nickels, how many of each type of coin was​ collected?
Answered by Reiny
number of nickels --- x
number of dimes ----- 5x

5x + 10(5x) = 5775

solve for x, it is easy
Answered by kid
You need to use a system of equations. Lets say that N equals the number of nickels, and D is the number of dimes.

D = 5 x N

because there are 5 times as many dimes as nickels

.05N + .1D = 57.75

the .05 and .1 represent the value of the coins (N is 5 cents, D is 10)

Well, you know the value of D is 5 x N, so you can substitute it into the problem

.05N + .1(5 x N) = 57.75
.05N + .5N = 57.75
.55N = 57.75
N = 105

Now that you know the number of nickels, plug the value back into the first equation to find out the number of dimes

D = 5 x N
D = 5 x 105
D = 525

So the answer is 105 nickels and 525 dimes
Answered by Anonymous
Jessica has a handful of nickels and quarters worth a total of ​$5.455. If she has seven more nickels than​ quarters, how many of each type of coin does she​ have?
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