Asked by carolina
if k=log(squareroot9+squareroot5)/log(2), express log(squareroot9-squareroot5)/log(squareroot2) in terms of k.
Answers
Answered by
bobpursley
k=log(squareroot9+squareroot5)/log(2)
k=log(squareroot9+squareroot5)/2log(sqrt2)
2k=log(squareroot9+squareroot5)/ log(sqrt2)
k=log(squareroot9+squareroot5)/2log(sqrt2)
2k=log(squareroot9+squareroot5)/ log(sqrt2)
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