Asked by Anonymous

Find the perimter and area of a 45-45-90 degree triangle with hypotenuse length of 10 centimeters.

P=20 square root 2 cm?
A=50 cm ^2
Answered by AlphaPrimes
This is just a right triangle... Use SOHCAHTOA to solve for each side and you can find the perimeter... Area of a triangle =b*h/2
Answered by Steve
Each leg is 10/√2, so
P = 2*10/√2 + 10 = 10(1+√2)
A = (1/2)(10/√2)(10/√2) = 100/4 = 25
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