Asked by Ashraf
Block A, with a mass of 26 kg, rests on a 38° incline. The coefficient of kinetic friction is 0.46. The attached string is parallel to the incline and passes over a massless, frictionless pulley at the top. Block B, with a mass of 37 kg, is attached to the dangling end of the string. The acceleration of B is:
Answers
Answered by
bobpursley
force of gravity down plane:
-massA*g*SinTheta
friction down the plane (assumed direction):
=massA*g*mu*Costheta
pulling force up the plane
massB*g
net force=total mass*a
massB*g-massA*g*sinTheta-massA*g*mu*CosTheta =(massA+MassB)a
now solve for a. If you chose the wrong assumed direction for friction, it will show up in the sign of acceration.
-massA*g*SinTheta
friction down the plane (assumed direction):
=massA*g*mu*Costheta
pulling force up the plane
massB*g
net force=total mass*a
massB*g-massA*g*sinTheta-massA*g*mu*CosTheta =(massA+MassB)a
now solve for a. If you chose the wrong assumed direction for friction, it will show up in the sign of acceration.
Answered by
Anonymous
pak u ka
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