Asked by Brian
A transformer with 1890 turns in its primary coil has to decrease the voltage from 4620 V to 220 V for home use. How many turns should there be on the secondary coil?
Answers
Answered by
bobpursley
N=secondaryvoltage/primaryvolts
N=4620/220=41
secondaryturns=N*primaryturns
= 41*1890
N=4620/220=41
secondaryturns=N*primaryturns
= 41*1890
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