Asked by John
Given overall reaction: P4 + 10Cl2 ---> 4PCl5 Delta H for the reaction = ?
PCl5 -----> PCl3 + Cl2 Delta H = +157 kJ
P4 + 6Cl2 ----> 4PCl3 Delta H = -1207 kJ
Calculate the Delta H for the overall reaction.
PCl5 -----> PCl3 + Cl2 Delta H = +157 kJ
P4 + 6Cl2 ----> 4PCl3 Delta H = -1207 kJ
Calculate the Delta H for the overall reaction.
Answers
Answered by
bobpursley
P4+10Cl2>>4PCl3 + 4 Cl2 H=-1207kJ
4PCl3+4Cl2>>4PCl5 H=-157*4 kJ
total? add the two H
4PCl3+4Cl2>>4PCl5 H=-157*4 kJ
total? add the two H
Answered by
Anonymous
-5456
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