the first and last numbers must be perfect squares. So, B is out.
The middle number must be twice the product of the roots of the 1st and last, since
(a+b)^2 = a^2+2ab+b^2
If we check 9x^2+9x+1, a=3 and b=1, but that would need 2*3*1 = 6x in the middle. So, (A) is out.
Check the other two.
Select the polynomial that is a perfect square trinomial.
9x2 + 9x + 1
36b2 − 24b + 8
16x2 + 24x + 9
4a2 − 10a + 25
4 answers
the third one
correct.
I don't get how you get to that conclusion, Help?
1 answer