Ask a New Question

Asked by mesha

how do i factor the polynomials using the ax2+bx+c with a =1? The problem is -16+m^2 power-6m.
9 years ago

Answers

Answered by Steve
-16 + m^2 - 6m
m^2 - 6m - 16

so, what two factors of 16 differ by 6?

(m-8)(m+2)
9 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

factor the polynomials 3n(squared)+8n=4 8x(to the third) - 6x(squared) - 27x - 54 Factor into polynomials with integral coefficients: 6x^2+13x+6 factor the polynomials using whatever strategy seems appropriate. 12m^2n^2-8mn+1 factor the polynomials x^2 -6 x^2 +5x-6 Two polynomials P and D are given. Use either synthetic or long division to divide P(x) by D(x),... polynomials 8j^3-4jk^3-7 Add these 2 polynomials (21t+8)(4t) and (3t-4)(2t) 84t^2+32t 6t^28t I got this far i... the sum of two polynomials is 40x^5-2x^4+x^3-7x^2-1. if the polynomial is the square of (x^2-7x+1),... Two polynomials P and D are given. Use either synthetic or long division to divide P(x) by D(x), and... Add the polynomials. (7x^3y^2 + 14xy + 14) + (3xy - 2x^3y^2 - 7) Question 1 options: A) 5x^3y^2...
Submit Your Answer

Question

how do i factor the polynomials using the ax2+bx+c with a =1? The problem is -16+m^2 power-6m.

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use