sin1.5deg=560/distance solve for distance....where distance is the actual distance, not horizontal distance. If a torpedo went the horizontal distance, it would be short.
time=2*distanceabove/velocitysound
time=2*distanceabove/velocitysound
First, let's convert the depth of the submarine from feet to yards. Since 1 yard is equal to 3 feet, the submarine is at a depth of 560/3 = 186.67 yards below the surface.
Now, we can set up a right triangle to represent the situation. The submarine's depth is the opposite side, and the distance from the submarine to the ship is the adjacent side. The angle of elevation, 1.5 degrees, is the angle between these two sides.
The formula to find the adjacent side of a right triangle is:
Adjacent side = Opposite side / tan(angle)
Using this formula, we can calculate the adjacent side:
Adjacent side = 186.67 / tan(1.5 degrees)
Adjacent side ≈ 6670.35 yards
Therefore, the actual distance from the submarine to the ship is approximately 6670.35 yards.
Now, let's calculate the time it will take for the sonar signal to get back to the submarine.
Since the sonar travels through seawater at an average velocity of 1500 meters/second, we need to convert the distance from yards to meters.
1 yard ≈ 0.9144 meters
So, the distance from the submarine to the ship in meters is:
6670.35 yards * 0.9144 meters/yard ≈ 6109.31 meters
To find the time it takes for the sonar signal to travel this distance, we can use the formula:
Time = Distance / Velocity
Time = 6109.31 meters / 1500 meters/second
Time ≈ 4.07 seconds
Therefore, it will take approximately 4.07 seconds for the sonar signal to get back to the submarine after it is released.