Asked by Superstix
four positive integers form an arithmetic progression . if the product of the first and the last terms is 70 and the second and third terms are 88, find the first term
Answers
Answered by
Steve
a(a+3d) = 70
(a+d)(a+2d) = 88
Since 88=8*11, I'd guess that
T2=8 and T3 = 11
so, that makes T1=5 and T3=15
or, you can solve the equations using algebra.
(a+d)(a+2d) = 88
Since 88=8*11, I'd guess that
T2=8 and T3 = 11
so, that makes T1=5 and T3=15
or, you can solve the equations using algebra.
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