Ask a New Question

Question

A block of mass 6 kg is accelerating at 1.25 m/s ,on the horizontal surface, under the action of a horizontal force of magnitude 22.5 N . Calculate the coefficient of friction between the block and the surface.
9 years ago

Answers

Henry
Wb = M*g = 6 * 9.8 = 58.8 N. = Wt. of block = Normal(Fn).

Fap-Fk = M*a, 22.5-Fk = 6*1.25 = 7.5, Fk = 15 N. = Force of kinetic friction.

u = Fk/Fn = 15/58.8 = 0.255.


9 years ago

Related Questions

a block of mass 2 kg and block B of mass 8 kg are connected by a spring of spring constant 80 N/m an... Block A (mass 40 kg) and block B (mass 80 kg) are connected by a string of negligible mass as shown... a motor of mass 1500 kg accelerates from 50 km/h to 100 km/h in 10 seconds.calculate. (i)The accele... A vehicle of known mass accelerates along a straight path. What cased this acceleration, accordi... A vehicle of known mass accelerates along a straight path. What cased this acceleration, accordi... How do force, mass, and acceleration relate to one another? (Choose 3) Responses A If force, F, is... Shows how force mass in acceleration are related commonly shown with the formula F equals MA is This is equal to mass x acceleration in the second law of motion. It is also the ability to apply a... A vehicle of known mass accelerates along a straight path. According to Newton's second law of motio... Force equals mass times acceleration.
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use