Asked by Andre
How do you find the derivative of sqrt(x+sqrt(x+sqrt(x+.......)))?
Answers
Answered by
Steve
y = √(x+√(x+√(x+...)))
y^2 = x+√(x+√(x+...)))
y^2 = x+y
2yy' = 1+y'
y' = 1/(2y-1) = 1/[2√(x+√(x+...)))-1]
y^2 = x+√(x+√(x+...)))
y^2 = x+y
2yy' = 1+y'
y' = 1/(2y-1) = 1/[2√(x+√(x+...)))-1]
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