Asked by rian
Determine the roots of the quadratic equation by completing the square. Solve for exact solutions and approximate solutions. Check your solutions.
Y=x2-6x-12
Y=x2-6x-12
Answers
Answered by
Steve
x^2-6x - 12
(x^2-6x+9) - 12-9
(x-3)^2 - 21
so, setting
(x-3)^2 - 21 = 0
(x-3)^2 = 21
x-3 = ±√21
x = 3±√21
(x^2-6x+9) - 12-9
(x-3)^2 - 21
so, setting
(x-3)^2 - 21 = 0
(x-3)^2 = 21
x-3 = ±√21
x = 3±√21
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