Asked by Mayiisah
From point A,the angle of elevation to the top of a tall building is 20 degrees.On walking 80 m towards the building,the angle of elevation is now 23 degrees.How tall is the building?
Answers
Answered by
Reiny
Make a sketch, label the top of the building P and its bottom Q.
On the ground, label angle A = 20 and mark point B as 23 degrees
then angle ABP = 180-23 = 157 degrees
angle A = 20 and angle APB = 3 degrees
by the sine law
BP/sin20 = 80/sin3
BP = 80sin20/sin3
= ....
then in the right-angled triangle BPQ
sin 23 = PQ/BP
take over
On the ground, label angle A = 20 and mark point B as 23 degrees
then angle ABP = 180-23 = 157 degrees
angle A = 20 and angle APB = 3 degrees
by the sine law
BP/sin20 = 80/sin3
BP = 80sin20/sin3
= ....
then in the right-angled triangle BPQ
sin 23 = PQ/BP
take over
Answered by
stanley
h= 220.95m
Answered by
stanley
stanley u are wrong the answer is 204.1m
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