Asked by Bel
At the moment of release each plane has the same speed of 186 m/s, and each tank is at the same height of 3.11 km above the ground. Although the speeds are the same, the velocities are different at the instant of release, because one plane is flying at an angle of 15.0° above the horizontal and the other is flying at an angle of 15.0° below the horizontal. Find the (a) magnitude and (b) direction of the velocity with which the fuel tank hits the ground if it is from plane A. Find the (c) magnitude and (d) direction of the velocity with which the fuel tank hits the ground if it is from plane B. In each part, give the direction as a positive angle with respect to the horizontal.
Answers
Answered by
Chanz
vx is the same for both (186cos15)
vy is either positive or negative 186sin15. Use 2gy = vf^2-vi^2 to find the two vy's
Then pythag and tan-1
vy is either positive or negative 186sin15. Use 2gy = vf^2-vi^2 to find the two vy's
Then pythag and tan-1
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