Asked by Anonymous
I have 3 flavors of ice cream and 38 toppings how many combinations can I make
Answers
Answered by
Reiny
You used the word "combination" which implies that the order does not matter.
We will also assume that flavours cannot be repeated, e.g. no double-vanilla
Number of combinations
= C(38,3)
= 38!/(3!35!)
= 8436
We will also assume that flavours cannot be repeated, e.g. no double-vanilla
Number of combinations
= C(38,3)
= 38!/(3!35!)
= 8436
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