Asked by nicole
Write an equation for a cosecant function with a period of 3𝜋 and a range of (−‡,−2]¾[2,‡)
Answers
Answered by
Reiny
so you want y = a csc (2/3)x
where a is whatever your (−‡,−2]¾[2,‡) means
well, y = csc (2x/3) looks like this:
http://www.wolframalpha.com/input/?i=plot+y+%3D+csc+(2x%2F3)
the vertical lines are asymptotes at
x = 0, ±3π/2, ± 3π, ...
the range is y ≥1 OR y ≤ -1
where a is whatever your (−‡,−2]¾[2,‡) means
well, y = csc (2x/3) looks like this:
http://www.wolframalpha.com/input/?i=plot+y+%3D+csc+(2x%2F3)
the vertical lines are asymptotes at
x = 0, ±3π/2, ± 3π, ...
the range is y ≥1 OR y ≤ -1
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