(p1v1/t1) = (p2v2/t2)
Remember T must be in kelvin.
Remember T must be in kelvin.
1.325/250.0K
m=.0053
The formula for the combined gas law is:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures.
Let's plug in the given values:
P1 = 1.02 atm
V1 = 2.20 L
T1 = 57°C (which needs to be converted to Kelvin by adding 273.15)
P2 = 0.789 atm
V2 = ? (what we need to find)
T2 = 107°C (which needs to be converted to Kelvin by adding 273.15)
Using the formula, we can rearrange it to find V2:
V2 = (P1 * V1 * T2) / (P2 * T1)
Now let's plug in the values and calculate:
V2 = (1.02 atm * 2.20 L * (107°C + 273.15)) / (0.789 atm * (57°C + 273.15))
V2 = (1.02 atm * 2.20 L * 380.15 K) / (0.789 atm * 330.15 K)
V2 = (898.32 L atm K) / (261.12 atm K)
V2 ≈ 3.440 L
Therefore, the gas would occupy approximately 3.440L at 107°C and 0.789 atm.