Asked by aly
I did a lab on the colorimetric determination of iron concentration and I'm not sure how to convert fe conc into ppm. For example, how would i convert 0.6 ug/ml to ppm?
Answers
Answered by
Olereb48
ppm is a weight/weight ratio problem. That is, weight of solute/weight of solution... I am assuming the 0.60ug is in water having a density of 1g/ml. (Sounds like you are running the FeSCN+2 Kc experiment). Anyways, given 0.60ug/ml = 0.6ug solute/1.0g solution = 6 x 10^-7g solute/1.0g Solution. By converting dimensions to same units one gets the ratio as the fractional ratio for solute in solution. Therefore for ppm, multiply ratio by 1 x 10^6. That is,
(6 x 10^-7/1)(1 x 10^6)ppm = 0.6ppm.
Converting solution concentrations to (gms solute/gms solution) gives a fractional wt/wt ratio that can be converted to % (parts per hundred), ppm or ppb by simply multiplying the ratio by 100 for %, 1-million for ppm, or 1-billion for ppb.
(6 x 10^-7/1)(1 x 10^6)ppm = 0.6ppm.
Converting solution concentrations to (gms solute/gms solution) gives a fractional wt/wt ratio that can be converted to % (parts per hundred), ppm or ppb by simply multiplying the ratio by 100 for %, 1-million for ppm, or 1-billion for ppb.
Answered by
aly
I understand it now, thank you so much!
Answered by
DrBob222
A very easy way to do these ppm problem in water solution is to remember that 1 ppm = 1 mg/L or 1 ug/mL.
So 0.6 ug/mL = 0.6 ppm.
So 0.6 ug/mL = 0.6 ppm.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.