Asked by Komal

train moving with speed 72 km h−1
emits a whistle of frequency 600 Hz. A
person is standing stationary on the platform. Calculate the frequency heard by the
person if the train (i) approaches and (ii) recedes away from the listener.

Answers

Answered by Henry
Vt = 72,000m/h * 1h/3600s = 20 m/s.

a. Fp = (Vs+Vp)/(Vs-Vt) * Ft =(343+0)/(343-20) * 600 = 637.2 Hz.

b. Fp = (Vs-Vp)/(Vs+Vt) * Ft =

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