Asked by jo
What is the ratio of the area of sector AOB to the area of sector COD?
1/3,1/4,1/9,3/8
1/3,1/4,1/9,3/8
Answers
Answered by
Steve
Since the area is 1/2 r^2 θ, the ratio is
1/2 r^2 m∠AOB
--------------- = (m∠AOB)/(m∠COD)
1/2 r^2 m∠COD
That is, since for a given circle, the area is directly proportional to the angle, the ratio of the areas is the same as the ratio of the angles.
I have no idea what that ratio is, but it must be one of the choices.
1/2 r^2 m∠AOB
--------------- = (m∠AOB)/(m∠COD)
1/2 r^2 m∠COD
That is, since for a given circle, the area is directly proportional to the angle, the ratio of the areas is the same as the ratio of the angles.
I have no idea what that ratio is, but it must be one of the choices.
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