Question
an air balloon is 80ft away from you with the angle of elevation of the rising balloon changing at a rate of 4 degrees per second how fast is the balloon rising when it is 6 feet off the ground.
Answers
assuming the 80 ft is along the ground,
h/80 = tanθ
1/80 dh/dt = sec^2θ dθ/dt
when h=6, sec^2θ = 1+tan^2θ = 1+(6/80)^2 = 1.0056
1/80 dh/dt = 1.0056 * 4*π/180
dh/dt = 5.6 ft/s
h/80 = tanθ
1/80 dh/dt = sec^2θ dθ/dt
when h=6, sec^2θ = 1+tan^2θ = 1+(6/80)^2 = 1.0056
1/80 dh/dt = 1.0056 * 4*π/180
dh/dt = 5.6 ft/s
Related Questions
A balloon is rising vertically above a level, straight road at a constant rate of 1 foot/second. Jus...
A balloon, 50 feet from an observer is rising at 20 ft/sec. At 5 sec after lift off,
a)how fast i...
A hot air balloon, 50 feet from an observer, is rising at 20 ft/sec. At 5 seconds after lift off
1...
A balloon, 50 feet from an observer, is rising at 20 ft/sec. At 5 seconds after lift off
1. How f...