Asked by Vikram
                An object has a constant acceleration of 40 ft/sec2, an initial velocity of -20 ft/sec, and an initial position of 10 ft
            
            
        Answers
                    Answered by
            Steve
            
    well, you know that
a = 40
v = ∫a dt = 40t + a
s = ∫v dt = 20t^2 + at + b
use the given conditions to find a and b.
    
a = 40
v = ∫a dt = 40t + a
s = ∫v dt = 20t^2 + at + b
use the given conditions to find a and b.
                    Answered by
            Rickity Sanchez
            
    s(t)= (20t sqrd -20t +10) 
Use the formula
s(t)= (1/2)a tsqrd + V0t + S0
    
Use the formula
s(t)= (1/2)a tsqrd + V0t + S0
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