Asked by Vikram
An object has a constant acceleration of 40 ft/sec2, an initial velocity of -20 ft/sec, and an initial position of 10 ft
Answers
Answered by
Steve
well, you know that
a = 40
v = ∫a dt = 40t + a
s = ∫v dt = 20t^2 + at + b
use the given conditions to find a and b.
a = 40
v = ∫a dt = 40t + a
s = ∫v dt = 20t^2 + at + b
use the given conditions to find a and b.
Answered by
Rickity Sanchez
s(t)= (20t sqrd -20t +10)
Use the formula
s(t)= (1/2)a tsqrd + V0t + S0
Use the formula
s(t)= (1/2)a tsqrd + V0t + S0
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