Asked by nate
An executive traveling at 60 km hr would arrive 10 minutes early for an appointment, whereas at a speed of 45 km hr the executive would arrive 5 minutes early.how much time is there until the appointment?
Answers
Answered by
Henry
T = Time until app.
60*(T-10/60) = 45*(T+5/60),
60T-10 = 45T + 3.75,
15T = 13.75, T = 0.91667 h = 55 Min.
60*(T-10/60) = 45*(T+5/60),
60T-10 = 45T + 3.75,
15T = 13.75, T = 0.91667 h = 55 Min.
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