Asked by Venkatesh
sum of 4 terms of g p is 30 & sum of first and last term is 18 . Find gp
a(r^4-1)/(r-1) = 30
a + ar^3 = 18
a(1+r^3) = 18
it's easy to see that if a=2, r=2
Does that work on S4?
2*15/1 = 30. Yes
So, the GP is
2,4,8,16,...
But sir I want not logic proof , please give complete proof
a(r^4-1)/(r-1) = 30
a + ar^3 = 18
a(1+r^3) = 18
it's easy to see that if a=2, r=2
Does that work on S4?
2*15/1 = 30. Yes
So, the GP is
2,4,8,16,...
But sir I want not logic proof , please give complete proof
Answers
Answered by
Steve
Geez, guy, you're not gonna work on it at all?
a = 30(r-1)/(r^4-1)
a = 18/(1+r^3)
30(r-1)(1+r^3) = 18(r^4-1)
30(r^4-r^3+r-1) = 18(r^4-1)
2r^4-5r^3+5r-2 = 0
I'll let you factor that and find that r=2 is a root.
a = 30(r-1)/(r^4-1)
a = 18/(1+r^3)
30(r-1)(1+r^3) = 18(r^4-1)
30(r^4-r^3+r-1) = 18(r^4-1)
2r^4-5r^3+5r-2 = 0
I'll let you factor that and find that r=2 is a root.
Answered by
Venki
Sir I only know to solve quadratic equation.
Answered by
Steve
well, I gave you a hint. Try some synthetic division. You know that any rational roots must be found among
±1, ±1/2, ±2
±1, ±1/2, ±2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.